Aufre
Ataberk   Turkey
 
 
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Comments
OGKA 19 May, 2020 @ 1:30pm 
sin(nx) = (e^(inx)-e^(-inx))/(2i)

= ((e^(ix))^n-(e^(-ix))^n)/(2i)
= ((cosx+isinx)^n-(cosx-isinx)^n)/(2i)
= sum_(k=0)^(n)(n; k)(cos^kx(isinx)^(n-k)-cos^kx(-isinx)^(n-k))/(2i)

= sum_(k=0)^(n)(n; k)cos^kxsin^(n-k)x(i^(n-k)-(-i)^(n-k))/(2i)

= sum_(k=0)^(n)(n; k)cos^kxsin^(n-k)xsin[1/2(n-k)pi].
bominto 25 Dec, 2019 @ 3:49am 
müslüman noel mi kutlar arsız
bominto 21 May, 2019 @ 3:11pm 
helo çildır haw are u todey